解:原式=x3+x2y﹣x2y+y3(第一步)
=(x3+x2y)﹣(x2y﹣y3)(第二步)
=x2(x+y)﹣y(x2﹣y2)(第三步)
=x2(x+y)﹣y(x+y)(x﹣y)(第四步)
= .
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