#获取动态的8位字符串s,过程略
num = 0
p = ""
for i in s:
if "0" <= i <= "9":
num = num + int(i)
elif "a" <= i <= "z":
p = p + chr(ord(i) - 32)
elif "A" <= i <= "Z":
p = p + chr((ord(i) - ord("A") + 3) % 26 + ord("A"))
p = p + str(num % 10) + str(num // 10)
print("验证码为:",p)
若动态字符串s 为"8Y!5u23_",则运行程序段后,输出验证码为( )