num = input("请输入数字串:")
c = 0
⑴
for i in range(1,len(num)):
if ⑵ and f == False:
f = True
elif ⑶ and f == True:
c = c + 1
f = False
print("该数字串中有", c, "个拐点")
方框(1)(2)(3)的代码由以下部分组成:
①f = True ②f = False ③num[i-1] > num[i] ④num[i-1] < num[i]
下列选项中代码顺序正确的是( )