一、选择题:(本大题10小题,每小题3分,共30分)
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A . 8
B . 4
C .
D .
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A .
B . 0
C . 1
D .
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A . 7的算术平方根是49
B . 同旁内角互补
C . 相等的角是对顶角
D . 若a∥b,b∥c,则a∥c
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A . 第一象限
B . 第二象限
C . 第三象限
D . 第四象限
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10.
(2024七下·龙湖期中)
如图,在平面直角坐标系中,已知点
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmi%3EA%3C%2Fmi%3E%3Cmrow%3E%3Cmo%3E%28%3C%2Fmo%3E%3Cmrow%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E%2C%3C%2Fmn%3E%3Cmn%3E1%3C%2Fmn%3E%3C%2Fmrow%3E%3Cmo%3E%29%3C%2Fmo%3E%3C%2Fmrow%3E%3Cmn%3E%2C%3C%2Fmn%3E%3Cmi%3EB%3C%2Fmi%3E%3Cmrow%3E%3Cmo%3E%28%3C%2Fmo%3E%3Cmrow%3E%3Cmo%3E%E2%88%92%3C%2Fmo%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E%2C%3C%2Fmn%3E%3Cmn%3E1%3C%2Fmn%3E%3C%2Fmrow%3E%3Cmo%3E%29%3C%2Fmo%3E%3C%2Fmrow%3E%3Cmn%3E%2C%3C%2Fmn%3E%3Cmi%3EC%3C%2Fmi%3E%3Cmrow%3E%3Cmo%3E%28%3C%2Fmo%3E%3Cmrow%3E%3Cmo%3E%E2%88%92%3C%2Fmo%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E%2C%3C%2Fmn%3E%3Cmo%3E%E2%88%92%3C%2Fmo%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmrow%3E%3Cmo%3E%29%3C%2Fmo%3E%3C%2Fmrow%3E%3Cmn%3E%2C%3C%2Fmn%3E%3Cmi%3ED%3C%2Fmi%3E%3Cmrow%3E%3Cmo%3E%28%3C%2Fmo%3E%3Cmrow%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E%2C%3C%2Fmn%3E%3Cmo%3E%E2%88%92%3C%2Fmo%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmrow%3E%3Cmo%3E%29%3C%2Fmo%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
, 点
P ,
Q同时从点
A出发,沿长方形ABCD的边作环绕运动,点
P按逆时针方向以每秒2个单位长度的速度匀速运动,点
Q按顺时针方向以每秒3个单位长度的速度匀速运动,则第2024秒P,Q两点相遇地点的坐标是( )
![](//tikupic.21cnjy.com/2024/05/13/a8/d3/a8d38e2f23e5656f42afc43e67b41413.png)
二、填空题 (本大题5小题,每小题3分,共15分)
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15.
(2024七下·龙湖期中)
如图,直线AB经过原点O,点C在y轴上,D为线段AB上一动点,若A(2,m),B(-3,n),C(0,-2),AB=10,则CD长度的最小值为
.
![](//tikupic.21cnjy.com/2024/05/13/23/b3/23b39a8160e2199afd8a3145a15e36cc_155x129.png)
三、解答题(一)(本大题2小题,每小题5分,共10分)
四、解答题(二)(本大题3小题,每小题7分,共21分)
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18.
(2024七下·龙湖期中)
如图,
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmo%3E%E2%88%A0%3C%2Fmo%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmo%3E%3D%3C%2Fmo%3E%3Cmo%3E%E2%88%A0%3C%2Fmo%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmath%3E)
,
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmo%3E%E2%88%A0%3C%2Fmo%3E%3Cmn%3E3%3C%2Fmn%3E%3Cmo%3E%3D%3C%2Fmo%3E%3Cmo%3E%E2%88%A0%3C%2Fmo%3E%3Cmi%3EE%3C%2Fmi%3E%3C%2Fmath%3E)
, 试说明:AD∥BE.
补全下列推理过程,并在括号内填写推理依据.
![](//tikupic.21cnjy.com/2024/05/13/e3/15/e3153d1c788eedc8078456ed649dbeae.jpeg)
∵
, (已知)
∴
∥_▲_,(_▲_)
∴
_▲_,(_▲_)
又∵
, (已知)
∴
_▲_,( ▲ )
∴AD∥BE.(_▲_)
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(2)
求
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmo%3E%E2%88%A0%3C%2Fmo%3E%3Cmi%3EB%3C%2Fmi%3E%3Cmi%3EO%3C%2Fmi%3E%3Cmi%3EE%3C%2Fmi%3E%3C%2Fmath%3E)
和
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmtext%3E%E2%88%A0%3C%2Fmtext%3E%3Cmi%3ED%3C%2Fmi%3E%3Cmi%3EO%3C%2Fmi%3E%3Cmi%3EF%3C%2Fmi%3E%3C%2Fmath%3E)
的度数.
五、解答题(三)(本大题3小题,每小题8分,共24分)
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(1)
点M在一、三象限的角平分线上,求点M的坐标;
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(1)
请画出△
ABC沿
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmi%3Ex%3C%2Fmi%3E%3C%2Fmath%3E)
轴向右平移3个单位长度,再沿
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmi%3Ey%3C%2Fmi%3E%3C%2Fmath%3E)
轴向上平移2个单位长度后的△
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmsup%3E%3Cmi%3EA%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmsup%3E%3Cmi%3EB%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmsup%3E%3Cmi%3EC%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3C%2Fmath%3E)
(其中
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmsup%3E%3Cmi%3EA%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmtext%3E%E3%80%81%3C%2Fmtext%3E%3Cmsup%3E%3Cmi%3EB%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmtext%3E%E3%80%81%3C%2Fmtext%3E%3Cmsup%3E%3Cmi%3EC%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3C%2Fmath%3E)
分别是
A、
B、
C的对应点,不写画法);
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(2)
直接写出
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmsup%3E%3Cmi%3EA%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmtext%3E%E3%80%81%3C%2Fmtext%3E%3Cmsup%3E%3Cmi%3EB%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3Cmtext%3E%E3%80%81%3C%2Fmtext%3E%3Cmsup%3E%3Cmi%3EC%3C%2Fmi%3E%3Cmn%3E%27%3C%2Fmn%3E%3C%2Fmsup%3E%3C%2Fmath%3E)
三点的坐标;
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(1)
证明:
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmi%3EA%3C%2Fmi%3E%3Cmi%3ED%3C%2Fmi%3E%3Cmo%3E%2F%3C%2Fmo%3E%3Cmo%3E%2F%3C%2Fmo%3E%3Cmi%3EE%3C%2Fmi%3E%3Cmi%3EF%3C%2Fmi%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
.
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六、解答题(四)(本大题2小题,每小题10分,共20分)
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(1)
若∠1与∠2都是锐角,如图1,请直接写出∠C与∠1,∠2之间的数量关系.
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(2)
若小明把一块三角板(∠A=30°,∠C=90°)如图2放置,点D,E,F是三角板的边与平行线的交点,若∠AEN=∠A,求∠BDF的度数.
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(3)
将图2中的三角板进行适当转动,如图3,直角顶点C始终在两条平行线之间,点G 在线段CD上,连结EG,且有∠CEG=∠CEM,
![](//math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmfrac%3E%3Cmrow%3E%3Cmo%3E%E2%88%A0%3C%2Fmo%3E%3Cmi%3EG%3C%2Fmi%3E%3Cmi%3EE%3C%2Fmi%3E%3Cmi%3EN%3C%2Fmi%3E%3C%2Fmrow%3E%3Cmrow%3E%3Cmo%3E%E2%88%A0%3C%2Fmo%3E%3Cmi%3EB%3C%2Fmi%3E%3Cmi%3ED%3C%2Fmi%3E%3Cmi%3EF%3C%2Fmi%3E%3C%2Fmrow%3E%3C%2Fmfrac%3E%3C%2Fmath%3E)
的值是否变化? 如果不变,求出比值;如果变化,请说明理由。
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(1)
如图1所示,平移线段AB到线段DC,使点A的对应点为D,点B的对应点为C,若点C的坐标为(-2,4),则点D的坐标为;、
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(2)
平移线段AB到线段DC,使点C在y轴的正半轴上,点D在第二象限内,连接BC,BD,如图2所示,若△BCD的面积为7,求点C、D的坐标;
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(3)
在(2)的条件下,在y轴上是否存在一点P,使△PBD与△BCD的面积之比为12∶7?若存在,求出点P的坐标;若不存在,请说明理由.