1.
已知：Fe2O3(s)＋3C(石墨)= 2Fe(s)＋3CO(g) ΔH＝＋489.0 kJ·mol−1①
CO(g)＋ 
O2(g)= CO2(g) ΔH＝−283.0 kJ·mol−1②
C(石墨)＋O2(g)= CO2(g) ΔH＝−393.5 kJ·mol−1③
则4Fe(s)＋3O2(g)= 2Fe2O3(s)的ΔH为( )
A . ＋1 164.1 kJ·mol−1
B . −1 641.0 kJ·mol−1
C . −259.7 kJ·mol−1
D . −519.4 kJ·mol−1
