解方程:x²-3|x|+2=0
解:(1)当x≥0时,原方程化为x²-3x+2=0,解得: =2, =1
( 2 )当x<0时,原方程化为x²+3x+2=0,解得: =1, =-2.
∴原方程的根是 =2, =1, =1, =-2.
请观察上述方程的求解过程,试解方程x²-2|x-1|-1=0.
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